python之列表（list）

namelist = []   #定义一个空列表
namelist2 = ["tom", "marry", "Bob"]
tlist = [3, 3.22, "Bob"]

namelist2 = ["tom", "marry", "Bob",6,3,1,1]
print(namelist2)
print(namelist2[0:4])    #从位置0到4（左开右闭），包括 0 1 2 3 四个位置
print(namelist2[0:6:2])   #从位置0到6（左开右闭），跨步值为2，分别为 0 2 4三个位置
print("-"*10)
for name in namelist2:
    print(name)

namelist2 = ["tom", "marry", "Bob",6,3,1,1]
#追加
print("追加前：名单数据")
for name in namelist2:
    print(name)
a=input("请输入追加的名字：")
namelist2.append(a)

print("追加后：名单数据")
for name in namelist2:
    print(name)

a = [1, 2]
b = ["jjj", "nknk", 2]
a.append(b)   # 将一个数组当作一个元素加入
print(a)
a.extend(b)   # 拆散逐一加入

print(a)

extend是将一个数组拆散逐一加入，append将一个数组当作一个元素加入

# 增：insert
a=[1,2,3]
a.insert(2,"jj")  # 第一个表示位置，第二个表示值
print(a)

movie=['加勒比海盗',"指环王","速度与激情","指环王"]
print(movie)

del movie[1]    #用 delete删除
print(movie)

movie.remove("指环王")  #删除指定内容(只删除第一个)
print(movie)

movie.pop()   # 弹出最后一个
print(movie)

namelist2 = ["tom", "marry", "Bob",6,3,1,1]
findname=input("输入查找名字：")

if findname in namelist2:
    print("是")
else:
    print("否")

a = ["a", "b", "b", "a", "b"]
print(a.index("b", 0, 4))   # 查找“a”是否出现在0到4的位置上（范围左闭右开，包含0不包含4）,如果是则返回第一个的具体位置
                            # 找不到会报错
print(a.count("b"))       #查找一下“b”的数量

#排序：
a=["a","b","e","d"]
a.reverse()  #反转
print(a)

a.sort()    #升序排列
print(a)

a.sort(reverse=True)   #降序排列
print(a)

#-*- coding = utf-8 -*-
#@Time :2022/1/23 16:16
#@Author :zzy
#@File :demo6.py
#@Software :PyCharm


cars=[]
flag=True
price = 0

while flag == True:
    products = [['iphone', 6888], ['小米6', 2499], ['华为', 3499], ['魅族', 2289], ['mac', 3999], ['Vivo', 2678]]
    i = 0
    j=-1
    k=0

    print("------商品列表--------")
    for product in products:
        print("%d    %s        %d" % (i, product[0], product[1]))
        i += 1

    choice=input("请选择商品编号：(q表示退出结账）\n")

    if choice == 'q':
        print("------购物车列表--------")
        for car in cars:
            print("%d    %s        %d     %d个" % (car[2], car[0], car[1], car[3]))

        print("总金额：%d"%price)
        break
    elif int(choice) <0 or int(choice) >=len(products):
        continue
    else:
        for num in cars:
            if "T"+choice in num:
                j=k
            k+=1

        if j!=-1:
            price = price + products[int(choice)][1]
            cars[j][3]=cars[j][3]+1

        else:
            price = price+products[int(choice)][1]
            products[int(choice)].append(0)
            products[int(choice)].append(0)
            products[int(choice)][3]=products[int(choice)][3]+1
            products[int(choice)][2]=int(choice)
            cars.append(products[int(choice)])
            cars[j].append("T"+choice)